tent ph larutan koh 0,0005 M

[oh] = 1 x 5 x 10^-4
[oh] = 5 x 10^-4

ph= - log[oh]
= -log 5x10^-4
= 4-log 5

poh= 14 - ph
= 14 -(4-log5)
= 10+log5