Matematika

Pertanyaan

Akar 32 - 3, akar2 + akar 98 ?

1 Jawaban


  • [tex]1.) \sqrt{32} - 3 \\ = \sqrt{16 \times 2} - 3 \\ = 4 \sqrt{2} - 3 \\ \\ 2.) \sqrt{2 } + \sqrt{98} \\ = \sqrt{2 } + \sqrt{49 \times 2} \\ = \sqrt{2} + 7 \sqrt{2 } \\ = 8 \sqrt{2} [/tex]

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