perhatikan gambar lingkaran dengan pusat O.  jika besar <AOD=56, besar <ACB=....

1 Jawaban

  • [tex]\ \textless \ BOD= 180^{o}[/tex]
    maka
    [tex]\ \textless \ AOB=180^{o}-\ \textless \ AOD\\ \ \textless \ AOB=180^{o}-56^{o}\\ \ \textless \ AOB=124^{o}\\[/tex]
    sehingga,
    [tex]\ \textless \ ACB= \frac{1}{2} \times \ \textless \ AOB \\ \ \textless \ ACB= \frac{1}{2} \times 124^{o} \\ \ \textless \ ACB=62^{o}\\[/tex]