Jika di ketahui f(x) =-x+3maka f(x²) +[f(x)] ²-2f(x)

jawab
fungsi

f(x) = - x + 3

f(x²)= - x² + 3
( f(x)² = (- x + 3)²  = x² - 6x + 9

f(x²) + [ f(x)]² - 2. f (x) = (- x² + 3) + (x²- 6x + 9)  - 2 (-x +3)
= -x² + 3  + x² -6x + 9 + 2x  - 6
= -x² + x²  - 6x + 2x + 3 + 9 - 6
= - 4x + 6