tolong ya matematika kls 2 sma :)

jawab
limit

2) limit (x->3) √(x²-4)
sub x = 3 , limit = √(9-4)= √5

3) limit(x-> 2) (-4x² + 6x - 8)/ (3x² +7x - 2)
sub x = 2 , limit = { -4(2)² +6(2) - 8 } / {3(2)² + 7(2) - 2}
limit = (-16 +12 - 8) / (12 + 14 - 2)
limit = (-12)/(24) 
limit = - 1/2

4) limit(x-> 4)  (√x - 2 )/(x - 4)
limit(x -> 4 )  (√x - 2 ) ./ {(√x - 2)(√x + 2)}
limit(x->4 )  1/  (√x  + 2 )
sub x = 4
limit =  1/ (√4  + 2) = 1/4

5. limit (x->0) { 2 - √(4 -x) }/ (x))
limit (x -> 0)  { (2 - √(4 - x))(2  + √(4 - x)}/ x (2 - √(4 -x))
limit (x-> 0) { 4- 4 + x)./ x ( 2 + √(4 - x))
limit (x->0)  x / x (2 + √(4 - x) )

limit (x ->0 )  1/ (2 + √(4 - x))
x= 0 --> 1/ (2 + √4) = 1/ 4
 

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