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jawab

Δ KLM siku siku  diL
sinM = 2/3  --> KL/MK= 2/3 dan KL = 10
MK = 3/2 x 10√5 = 15
ML = √(MK² - KL²) = √(225-100) = 125 = 5√5

cos M = ML/MK= 5√5 /(15) = 1/3 √5
tan M = KL/ML = 10/5√5 =  2/√5 = (2/5)√5