pada suatu segitiga siku-siku ABC,dengan sudut B=90°,AB=24cm danBC=7cm,hitunglah Sin A dan Cos A

[tex]ac = \sqrt{ {24}^{2} + {7}^{2} } = \sqrt{576 + 49} = \sqrt{625} = 25 [/tex]
[tex] \sin( \alpha ) = \frac{7}{25} \\ \cos( \alpha ) = \frac{24}{25} [/tex]

[tex]ac = \sqrt{ {ab}^{2} + {bc}^{2} } \\ = \sqrt{ {24}^{2} + {7}^{2} } \\ = \sqrt{625} \\ = 25 \\ \\ sian \: a = \frac{bc}{ac} = \frac{7}{25} \\ cos \: a = \frac{ab}{ac} = \frac{24}{25} [/tex]