panjang AC= A. 3 CM B. 3√3 CM C. 6 CM D. 6√3 CM jawab di kumpulkan sekarang

[tex] \sin(45) = \frac{ad}{3 \sqrt{2} } \\ \frac{1}{2} \sqrt{2 } = \frac{ad}{3 \sqrt{2} } \\ ad = 3 [/tex]

sin 30 = ad/ac
1/2 = 3/ac
ac = 6