Matematika

Pertanyaan

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1 Jawaban

  • phytagoras ya

    a.
    [tex] {r}^{2} = \sqrt{ {x}^{2} + {y}^{2} } = > \sqrt{ {14}^{2} + {48}^{2} } = > \sqrt{196 + 2304} = > \sqrt{2500} = > 50[/tex]
    b.
    [tex] {r}^{2} = \sqrt{ {x}^{2} + {y}^{2} } = > \sqrt{ {8}^{2} + {15}^{2} } = > \sqrt{64 + 225} = > \sqrt{289} = > 17cm[/tex]
    c.
    [tex] {y}^{2} = \sqrt{ {26}^{2} - {24}^{2} } = > \sqrt{676 - 576} = > \sqrt{100} = > 10cm[/tex]
    d.
    [tex] {y}^{2} = \sqrt{ {r}^{2} - {x}^{2} } = > \sqrt{ {37}^{2} - {12}^{2} } = > \sqrt{1369 - 144} = > 1225 = > 35cm[/tex]
    e.
    [tex] {x}^{2} = \sqrt{ {r}^{2} - {y}^{2} } = > \sqrt{ {9}^{2} - {5}^{2} } = > \sqrt{81 - 25} = \sqrt{56} = > 2 \sqrt{14} [/tex]

    maaf jika ada kesalahan...

    hehehehhehehehehehehehehehe


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