Sumbu simetri f(x)=2x²-2x-12

Kelas 10 Matematika
Bab Persamaan Kuadrat

f(x) = 2x² - 2x - 12
a = 2; b = -2; c = -12.

Sumbu simetri
= -b/2a
= - (-2)/(2 . -2)
= 2/-4
= -1/2

Jawabannya:

Mapel. : Matematika
Bab. : Pers. Kuadrat

Pembahasan:

Sumbu Simetri
f(x) = 2x² - 2x - 12
a → 2
b → -2

Jadi :

b = -b/2a
= -(-2)/2(-2)
= 2/-4
= - 1/2

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