assalamualaikum tolong jawab pd gambar ini

Mapel : Matematika
Materi : Akar Kuadrat

[tex](a+b)^2=a^2+2ab+b^2 \\ \\ (6 \sqrt{3}+2 \sqrt{2})(6 \sqrt{3}+2 \sqrt{2})=(6 \sqrt{3}+2 \sqrt{2})^2 \\ \\ =(6 \sqrt{3})^2+(2\times6 \sqrt{3}\times2 \sqrt{2})+(\sqrt{2})^2 \\ \\ =(6^2\times(\sqrt{3})^2)+(2\times6\times2\times\sqrt{3\times2})+(2^2\times(\sqrt{2})^2)\\ \\ =(36\times3)+(24\sqrt{6})+(4\times2) \\ \\ =108+24\sqrt{6}+8 \\ \\ =\boxed{\boxed{\bold{116+24\sqrt{6}}}}[/tex]

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Info Tambahan sesuai pertanyaan Dhaniel di komentar penjawab pertama :

[tex]Jika, (a-b)(a+b)=a^2-b^2 \\ \\=(6 \sqrt{3}-2 \sqrt{2})(6 \sqrt{3}+2 \sqrt{2}) \\ \\=(6 \sqrt{3})^2-(2 \sqrt{2})^2\\ \\ =(6^2\times(\sqrt{3})^2)-(2^2\times(\sqrt{2})^2)\\ \\ =(36\times3)-(4\times2) \\ \\ =108-8\\ \\ =\boxed{\boxed{\bold{100}}}[/tex]

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