Matematika

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tolong no 10 ya kakak2 trimakasih bnyk
tolong no 10 ya kakak2 trimakasih bnyk

1 Jawaban


  • [tex]2 {x}^{2} + x + 6 = 0[/tex]
    a = 2 b = 1 c = 6
    [tex] \alpha + \beta = \frac{ - b}{a} = \frac{ - 1}{2} \\ \alpha \beta = \frac{c}{a} = \frac{6}{2}[/tex]
    [tex] \alpha^{2} + { \beta }^{2} = (\alpha + \beta )^{2} - 2 \alpha \beta \\ { \alpha }^{2} + { \beta }^{2} = { (\frac{ - 1}{2}) }^{2} - 2(\frac{6}{2} ) \\ { \alpha }^{2} + { \beta }^{2} = \frac{1}{4} - \frac{12}{2} \\ { \alpha }^{2} + \beta^{2} = \frac{1}{4} - \frac{24}{4} \\ { \alpha }^{2} + { \beta }^{2} = - \frac{23}{4} = - 5 \frac{3}{4} [/tex]
    Semoga dapat dipahami