besarnya pH larutan 1,48 Ca(OH)2 (Ar Ca = 40, O = 16, dan H = 1 dalam 1.000 mL larutan adalah

Mr Ca(OH)2 = 74

M = massa / (volume x Mr)
M = 1,48 / (1 x 74)
M = 2 x 10^-2

Ca(OH)2 dianggap asam kuat bervalensi 2

[OH-] = 2 x M
[OH-] = 2 x 2 x 10^-2
[OH-] = 4 x 10^-2
pOH = 2 - log4

pH = 14 - pOH
pH = 14 - (2 - log4)
pH = 12 + log4