Tlng pkai cara ya butuh

Dik:
c es = 2.100 J/kg derajat C
c air = 4.200 J/kg derajat C
L = 340.000 J/kg
m = 300 gr = 0,3 kg
Delta T = 0 - (-5) = 5

Dit:
Q1 + Q2

Jawab:

Q1 = m x c es x delta T
= 0.3 x 2.100 x 5
= 3.150 Joule

Q2 = m x L
= 0,3 x 340.000
= 102.000 Joule

Q1 + Q2 = 3.150 + 102.000
= 105.150 Joule . . . [D]