Efisiensi trafo tersebut adalah ....

diket :
Np = 1000
Ns = 200
Vp = 220 v
Ip = 1 A
Is = 4 A
dit : efisiensi
jwb :
# Teg. sekunder
Vs = ( Ns . Vp ) / Np
Vs = ( 200 . 220 ) /1000
Vs = 44.000 / 1000
Vs = 44 volt
# efisiensi trafo
ef = ( Is . Vs / Ip . Vp ) . 100%
ef = ( 4 . 44 / 1 . 220 ) . 100%
ef = ( 176 / 220 ).100%
ef = 80%