Matematika

Pertanyaan

S6 = 2009
S9 = 2010. U6?

1 Jawaban

  • S6=6/2(2a+5b)=2009
    S6=12a+30b=4018
    12a=4018-30b
    a=(4018-30b)/12

    S9=9/2(2a+8b)=2010
    S9=18a+72b=4020

    18a+72b=4020
    18(4018-30b)/12+72b=4020
    1,5(4018-30b)+72b=4020
    6027-45b+72b=4020
    27b=4020-6027
    b=-2007/27
    b=-223/3

    a=(4018-30b)/12
    a=(4018-30(-223/3))/12
    a=(4018+2230)/12
    a=6248/12
    a=1562/3

    Un=a+(n-1)b
    U6=a+5b
    U6=1562/3 + 5(-223/3)
    U6=1562/3 - 1115/3
    U6=447/3
    U6=149



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