Matematika

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  • [tex]15 \ \frac{1}{8} + 17 \ \frac{1}{2} + 12 \ \frac{3}{4} \\ = \frac{121}{8} + \frac{35}{2} + \frac{51}{4} \\ = \frac{121}{8} + \frac{140}{8} + \frac{102}{8} \\ = \frac{363}{8} \\ = 45 \ \frac{3}{8} [/tex]