Sebuah trafo memiliki tegangan primer dan skunder masing masing 200V dan 500V yang efisiennsinya 80% dgn kuat arus primer 10A. Hitunglah kuat arus listrik skund

diketahui
ч = 80 %
Vp = 200 V
Vs = 500 V
Ip = 10 A

ditanya
Is ........ ?

Jawab
ч = ( Vs x Is / Vp x Ip )x 100 %
80 % = ( 500Is ) / ( 200 x 10 ) x 100 %
80 % = ( 500 Is / ( 2000 ) x 100

50 Is = ( 80% / 100 % ) x 2000
50 IS = 4/5 x 2000
50 IS = 1600

Is = 1600/50
Is = 160/5
Is = 32 Ampere