suatu barisan geometri diketahui u2=6 dan u4=54. suku keenam adalah

U2 = ar
U2 = 6
ar = 6
a = 6/r

U4 = ar³
U4 = 54
ar³ = 54
a = 54/r³

a = a
6/r = 54/r³
r³/r = 54/6
r² = 9
r = √9
r = 3

a = 6/r
a = 6/3
a = 2

U6 = ar^5
U6 = 2 x 3^5
U6 = 486

semoga membantu ^^

dik:
barisan geometri Un = ar^n-1
U2 = 6
U2 = ar^2-1
6 = ar....... 1

U4 = 54
54 = ar^4-1
54= ar^3 ....... 2

ar^3 = 54
ar = 6
r^2 = 9
r = √9 = 3

substitusikan r = 3 ke persamaan 1
ar = 6
a. 3 =6
a = 6/3 = 2

U6 = ar^n-1
U6 = 2.3^6-1
= 486