Matematika

Pertanyaan

x+y-z=1
8x+3y-6z=1
-4x-y+3z=1

1 Jawaban

  • x + y - z = 1 
    -----------------x8
    8x + 8y - 8z = 8

    -4x - y + 3z = 1 
    ---------------------x2
    -8x - 2y + 6z = 2

    8x + 8y - 8z = 8
    8x + 3y - 6z = 1
    ---------------------- --
    5y - 2z = 7

    8x + 3y - 6z = 1
    -8x - 2y + 6z = 2
    ------------------------ +
    y = 3

    5(3) - 2z = 7
    15 - 2z = 7
    2z = 8
    z = 4

    x + y - z = 1
    x + 3 - 4 = 1
    x = 1 - 3 + 4
    x = 2

    Jadi, (x, y, z) = (2, 3, 4)

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