tolong bantu ya hari ini senin 29 jan 2018 mau dikumpul ok

Mapel : Matematika
Materi : Persamaan Kuadrat

[tex]=\frac{5x+2}{xy}+ \frac{x-5}{3} \\ \\ =\frac{3(5x+2)+xy(x-5)}{3xy}\\ \\ =\frac{15x+6+x^2y-5xy}{3xy}\\ \\ =\frac{x^2y+15x-5xy+6}{3xy}\\ \\ =\frac{x^2y+(5x(3-y))+6}{3xy} \\ \\ = \frac{x}{3}+ \frac{5(3-y)}{3y}+ \frac{2}{xy} \\ \\ = \frac{x}{3}+ \frac{5}{y}- \frac{5}{3}+ \frac{2}{xy}[/tex]

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