berapa hasil 2 cos 45 derajat + sec 45 derajat

[tex]2 \cos( {45}^{o} ) + \sec( {45}^{o} ) \\ = 2( \frac{1}{2} \sqrt{2} ) + \frac{1}{ \cos( {45}^{o} ) } \\ = \sqrt{2} + \frac{1}{ \frac{1}{2} \sqrt{2} } [/tex]
[tex] = \sqrt{2 } + \frac{2}{ \sqrt{2} } \\ = \sqrt{2} + (\frac{2}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } ) \\ = \sqrt{2} + \sqrt{2} [/tex]
[tex] = (1 + 1) \sqrt{2} \\ = 2 \sqrt{2} [/tex]

jadi, hasil 2 cos 45 derajat + sec 45 derajat adalah 2 akar 2