[tex]2 + \sqrt{6} \\ 3 + \sqrt{6} [/tex]
Matematika
Rahmaaini11
Pertanyaan
[tex]2 + \sqrt{6} \\ 3 + \sqrt{6} [/tex]
1 Jawaban
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1. Jawaban Natania01
[tex] \frac{2 + \sqrt{6} }{3 + \sqrt{6} } \times \frac{3 - \sqrt{6} }{3 - \sqrt{6} } \\ \\ = \frac{6 - 2 \sqrt{6 } + 3 \sqrt{6 } - 6 }{9 - 3 \sqrt{6} + 3 \sqrt{6 } - 6 } \\ \\ = \frac{ \sqrt{6} }{3} [/tex]