Matematika

Pertanyaan

x²+2x-8 per x²-2x-3 >o

1 Jawaban


  • [tex] \frac{ {x}^{2} + 2x - 8 }{ {x}^{2} - 2x - 3} > 0 = \frac{(x + 4)(x - 2)}{(x + 1)(x - 3)} > 0 [/tex]

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